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Teorema de Pitágoras

\text{Área do Anel}: A_{anel}=\pi a^2-\pi b^2\
\text{Área do Círculo}: A_{circ}=\pi c^2

b

a

c

A_{anel}=A_{circ}\quad\Longrightarrow\quad\pi a^2-\pi b^2=\pi c^2\quad \Longrightarrow\quad a^2=b^2+c^2

Solução

a = 6.281439977927592 rad (slider from 0° to 359.9°, step 0.1°)
A = Intersect(xAxis, yAxis)
c = Circle(A, 2)
B: ((2 * cos(a)), (2 * sin(a)))
f = Tangent(B, c)
C = Point(f)
g = Segment(B, C)
h = Segment(B, A)
i = Segment(A, C)
j = Segment(B, C)
D = (10, 0)
E: ((2.98 * cos(a - π / 2)), (2.98 * sin(a - π / 2))) + D
k = Segment(D, E)
l = Segment(B, D)
m = Segment(C, E)
n = Segment(D, E)
α = Angle(A, B, C)
b = true
F: (10, -2.98)
d = CircleSector(D, F, E)
G = (2, 2)
H = (5, 4)
u = Vector(G, H)
I = (9, 2)
J = (6, 4)
v = Vector(I, J)
mostrar: false
e = true